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Home/ Questions/Q 7830215
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T11:07:49+00:00 2026-06-02T11:07:49+00:00

When trying the execute the following in bash foo=foo my_array[$foo]=bar I get the error

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When trying the execute the following in bash

foo=foo
my_array[$foo]=bar

I get the error ‘bash: foo: expression recursion level exceeded (error token is “foo”)’. But this works fine:

foo=hello
my_array[$foo]=bar

Why is this happening?

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  1. Editorial Team
    Editorial Team
    2026-06-02T11:07:52+00:00Added an answer on June 2, 2026 at 11:07 am

    The problem is that you are not declaring your array to be associative, so it’s assumed to be a numeric array. When bash tries to evaluate

    my_array[$foo]=bar
    

    what he comes into is

    my_array[foo]=bar
    

    but the array index ain’t still numeric, so he tries to evaluate it again, leading into

    my_array[foo]=bar
    

    as you don’t need to use the $ when in between square brackets. You can see that this goes on and on until a recursion level exceeded exception is thrown.

    To solve it, just declare the array as associative:

    declare -A my_array
    
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