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Home/ Questions/Q 6998925
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T20:28:26+00:00 2026-05-27T20:28:26+00:00

when trying to define a function that would remove the largest subset of set

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when trying to define a function that would remove the largest subset of set m that is also a subset of set a from set a, I encountered the following error:

filename.hs:7:33:parse error (possibly incorrect indentation)

for the following code:

exclude :: Integral t => [t] -> [t] -> [t]
a `exclude` m
           | m == [] = a
           | a == (b ++ c) = b
           | otherwise = []
           where b /= []
           where c = [z | z <- m]

how do I implement multiple conditions/definitions (using where or otherwise), or correct the function to properly work in a different way?

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  1. Editorial Team
    Editorial Team
    2026-05-27T20:28:27+00:00Added an answer on May 27, 2026 at 8:28 pm

    Saying “the largest subset of set m that is also a subset of set a”
    is the same as saying “all elements of m that are also elements of a“.

    Then the solution to your problem is stated simply as:

    exclude a = filter (`notElem` a)
    

    which when applied to m will give you a subset of m modulo any elements
    that are also members of a. That is, it will “remove the largest subset of
    m that is also a subset of a“.

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