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Home/ Questions/Q 627623
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T19:32:55+00:00 2026-05-13T19:32:55+00:00

When using PHP’s json_decode() , I don’t see a way to distinguish between a

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When using PHP’s json_decode(), I don’t see a way to distinguish between a NULL return value indicating a failure in decoding and a correctly decoded NULL value:

var_dump(json_decode('nonsense')); // returns NULL
var_dump(json_decode(json_encode(NULL))); // also returns NULL

And case one doesn’t throw an exception. So I’m not sure how to test for a decode failure.

Ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-13T19:32:55+00:00Added an answer on May 13, 2026 at 7:32 pm

    You would have to check json_last_error for any JSON parsing errors.

    json_decode($string);
    switch(json_last_error()) {
        case JSON_ERROR_DEPTH:
            echo ' - Maximum stack depth exceeded';
        break;
        case JSON_ERROR_CTRL_CHAR:
            echo ' - Unexpected control character found';
        break;
        case JSON_ERROR_SYNTAX:
            echo ' - Syntax error, malformed JSON';
        break;
        case JSON_ERROR_NONE:
            echo ' - No errors';
        break;
    }
    
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