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Home/ Questions/Q 6879363
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:50:12+00:00 2026-05-27T04:50:12+00:00

When using the getaddrinfo method, I’m providing an IP address and the port number.

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When using the getaddrinfo method, I’m providing an IP address and the port number. I’m getting a linked list in the out variable. It works fine. But I have a conceptual doubt here. When i am giving both the IP address and port, how is it there are so many possible sockets returned? Shouldnt there be only one?

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:50:13+00:00Added an answer on May 27, 2026 at 4:50 am

    From the getaddrinfo man page:

    There are several reasons why the linked list may have more than one
    addrinfo structure, including: the network host is multihomed,
    accessible over multiple protocols (e.g. both AF_INET and AF_INET6);
    or the same service is available from multiple socket types (one
    SOCK_STREAM address and another SOCK_DGRAM address, for example).
    Normally, the application should try using the addresses in the order
    in which they are returned. The sorting function used within
    getaddrinfo() is defined in RFC 3484; the order can be tweaked for a
    particular system by editing /etc/gai.conf (available since glibc
    2.5).

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