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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T09:21:50+00:00 2026-06-17T09:21:50+00:00

When we are insert/lookup an key in a hash table, textbook said it is

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When we are insert/lookup an key in a hash table, textbook said it is O(1) time. Yet, how is possible to have an O(1) lookup time? If the hash table store the key in a vector, it will cost O(N), if in a binary tree, it will be O(logN). I just can’t image some data structure with O(1) accessing time.

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  1. Editorial Team
    Editorial Team
    2026-06-17T09:21:50+00:00Added an answer on June 17, 2026 at 9:21 am

    The hashtable hashes your key and put it in array.

    For example, hash(x) = 3, where x is your key. The table then puts it into array[3]. Accessing from array is O(1).

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