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Home/ Questions/Q 6370257
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T00:54:25+00:00 2026-05-25T00:54:25+00:00

When we include files in PHP, they are somehow cached. So, if one contains

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When we include files in PHP, they are somehow cached. So, if one contains a class definition, when we try to include it twice, we will get an error saying “Can not redeclare class”.

But is it possible to get include file code invoked with a scope set to current function, let’s say?

E.g. if we have two files:

moo.php:

<?php
class Moo
{
  function __construct()
  {
    echo "hello, world!" . PHP_EOL;
  }
}
?>

main.php:

<?php
function foo()
{
  include("moo.php");
  new Moo();
}

foo();

new Moo(); // <-- here should be an error saying "could not find class Moo"

include("moo.php");

new Moo(); // <-- and here should not
?>

As far as i’ve tried, not eval(file_get_contents("moo.php"));, nor namespaces either gave no expected effect with a least of code…

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  1. Editorial Team
    Editorial Team
    2026-05-25T00:54:26+00:00Added an answer on May 25, 2026 at 12:54 am

    Seems that monkey patching did the trick:

    <?php
    $code = <<<EOS
    namespace monkeypatch;
    
    \$s = "moofoo";
    
    echo "This should six, but is it?: " . strlen(\$s) . PHP_EOL;
    echo "Whoa! And now it is six, right?: " . \strlen(\$s) . PHP_EOL;
    
    function strlen(\$x) 
    {
        return -3.14;
    }
    EOS;
    
    eval($code);
    
    echo "While out of namespaces it is still six...: " . strlen("moofoo") . PHP_EOL;
    

    Lots of thanks to Marc B. for the hint!

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