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Home/ Questions/Q 7768773
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T15:59:59+00:00 2026-06-01T15:59:59+00:00

When we talk about atomic variables, such as C++11’s atomic<> , is it lock

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When we talk about atomic variables, such as C++11’s atomic<>, is it lock free? Or is lock-freeness something different? If I manage a queue with atomic variables, will it be slower than a lock-free queue?

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  1. Editorial Team
    Editorial Team
    2026-06-01T16:00:01+00:00Added an answer on June 1, 2026 at 4:00 pm

    The standard does not specify if atomic objects are lock-free. On a platform that doesn’t provide lock-free atomic operations for a type T, atomic<T> objects may be implemented using a mutex, which wouldn’t be lock-free. In that case, any containers using these objects in their implementation would not be lock-free either.

    The standard does provide a way to check if an atomic<T> variable is lock-free: you can use var.is_lock_free() or atomic_is_lock_free(&var). These functions are guaranteed to always return the same value for the same type T on a given program execution. For basic types such as int, There are also macros provided (e.g. ATOMIC_INT_LOCK_FREE) which specify if lock-free atomic access to that type is available.

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