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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:24:16+00:00 2026-05-13T10:24:16+00:00

Whenever I write a program in eclipse each line gets complied as go to

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Whenever I write a program in eclipse each line gets complied as go to next line.It shows compilation is done while writing he program only.
Does it mean javac.exe file is run whenever you write a line of program?
It debugging is much easier in Eclipse.

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:24:16+00:00Added an answer on May 13, 2026 at 10:24 am

    Eclipse has his own compiler (JDT). It does not use the javac.exe compiler. The question is how does it achieve such short compilation times?

    The internal data structure maintained by Eclipse for representing a Java program (AST) is the same data structure used by the JDT compiler. This sharing of data allows the compiler to run faster as it does not need to re-compile the whole program (or even the whole file) again.

    Also, unlike javac.exe the JDT compiler resides inside Eclipse. It is not a separate process so it does not need to be loaded (by the operating system) the same way javac.exe does.

    In addition to that (and this is true to all Java compilers), Java has dynamic linking. Each class is linked into the program when it is loaded during the execution of the program. This obviates the need for a linking phase at the end of compilation (a-la C/C++/C#). The linking phase is generally quite long as it processes the program as a whole (as opposed to compilation which is carried out on a a file-by-file basis). Thus, linking gets slower as the program grows. Techniques such as incremental linking have managed to mitigate this slow-down but not entirely.

    Given that Java needs no (static) linking, you can get to a state where a Java program is ready to run much faster than in other (statically linked) languages.

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