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Home/ Questions/Q 8756577
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T14:06:53+00:00 2026-06-13T14:06:53+00:00

Where: ssize is the input size of the array, student is a globally declared

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Where: ssize is the input size of the array, student is a globally declared struct, and read_stud is the function i use to read in arrays.

when printed out, s[count].first gives me the correct first name, but s[0] and all values after that are ALSO the same first name instead of the previously inputted value. It’s changing the struct values to my most recent input!

struct student //this struct is global
{
    int number;
    char *first ;
    char *last ;
};

struct student read_stud (int number, char *first , char *last) //my read_stud function
{
    struct student s;
    s.number = number;
    s.first = first;
    s.last = last;
    return s;
}

This is in int main, where I use the function s = calloc(ssize, sizeof (struct student));

for (count = 0; count < ssize ; ++count)
{
    printf ("Enter student number, name and last name: \n");
    scanf ("%d %s %s", &number, &first, &last);
    s[count] = read_stud (number, first, last); 
}

A most heartfelt thanks to whoever can fix this for me!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T14:06:54+00:00Added an answer on June 13, 2026 at 2:06 pm

    You need to provide storage for the first and last names in your student struct.

    If you know what their max lengths are, use char arrays in the struct.

    #define MAX_NAME_CHARS (20)
    
    struct student //this struct is global
    {
        int number;
        char first[MAX_NAME_CHARS];
        char last[MAX_NAME_CHARS];
    };
    

    Otherwise, malloc the strings and remember to free them later.

    struct student read_stud (int number, char *first , char *last) //my read_stud function
    {
        struct student s;
        s.number = number;
        s.first = strdup(first);
        s.last = strdup(last);
        return s;
    }
    
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