Question

Which I’m trying to accomplish is have two classes, a non generic and a generic.

I need a non generic class because I plan to insert objects of this class and insert them in a List<T>

Here’s the code

// Non-generic
public class Response
{
    public object Value { get; }
}

// Generic
public class Response<T> : Response
{
    public T Value { get; set; }
}

I’d like to have a List<Response>, where when I access to this object I get the Value property as object.

But when I receive this object as generic, access to the T Value property and hide the object Value property.

I hope be clear, if not.. please let me know.

EDIT: This is for a quiz. So, each question has answers.. For example in MultipleChoiceQuestion, it could have several answers A, B, C, D as view shapes, or could be strings, or integers.

public abstract class Question
{
    public Question(string questionText)
    {
        this.QuestionText = questionText;
    }

    public string QuestionText { get; set; }
}

// Non-generic
public class Response
{
    public object Value { get; }
}

// Generic
public class Response<T> : Response
{
    public T Value { get; set; }
}

public class MathProblemQuestion : Question
{
    public Response Response { get; set; }
}

public class MultipleChoiseQuestion : Question
{
    public Response Response { get; set; }

    public IEnumerable<Response> PossibleResponses;

    ...
}

public class TrueOrFalse : Question
{
    ...
}

Answer 1

I would personally just give them different names. It will make your life much simpler, and the code much clearer:

public abstract class Response
{
    public abstract object ObjectValue { get; }
}

public class Response<T> : Response
{
    public T Value { get; set; }

    public override object ObjectValue { get { return Value; } }
}

Note that I’ve made the Response class abstract – it’s hard to see how it could work elegantly otherwise; if Response has its own storage for Value then presumably that could be set to a non-T value. Hopefully making this abstract won’t be a problem for you.