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Home/ Questions/Q 7930347
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T20:23:32+00:00 2026-06-03T20:23:32+00:00

Which is best practice (in this case): bool Foo::operator==(const Foo& other) { return bar

  • 0

Which is best practice (in this case):

bool Foo::operator==(const Foo& other) {
  return bar == other.bar;
}

// Implementation 1
bool Foo::operator!=(const Foo& other) {
  return bar != other.bar
}

// Implementation 2
bool Foo::operator!=(const Foo& other) {
  return !(*this == other);
}

For operators like >, <, <=, >= I would go with implementation 2 when possible. However, for != I think implementation 1 is better since another method call is not made, is this correct?

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  1. Editorial Team
    Editorial Team
    2026-06-03T20:23:33+00:00Added an answer on June 3, 2026 at 8:23 pm

    The second implementation has the notable constraint that == will always be the boolean opposite of !=. This is probably what you want, and it makes your code easier to maintain because you only have to change one implementation to keep the two in sync.

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