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Home/ Questions/Q 6552637
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T12:29:03+00:00 2026-05-25T12:29:03+00:00

Which is more efficient statement –> goto &fun($val) or fun($val) in perl ? When

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Which is more efficient statement –> goto &fun($val) or fun($val) in perl ?
When to use which statement for better performance ?
Please let me know the answer !

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  1. Editorial Team
    Editorial Team
    2026-05-25T12:29:04+00:00Added an answer on May 25, 2026 at 12:29 pm

    I think this is the wrong question to ask.

    The form fun($val) is the standard way to call another subroutine in perl.

    The form goto &func is normally used to transfer control to another sub while removing the current stack frame. In addition, @_ is passed unaltered to the called routine.

    The removal of the stack frame means that caller() will not see it, so that the &func will think that t was called by the caller of the routine which performed the goto. It also means that performing a backtrace in the debugger will not reveal the routine performing the goto.

    If you want to preserve the calling stack frame but pass control to a function with the current setting of @_, then use return &func.

    The form goto &func($val) is parsed as:

    my $label = &func($val);
    goto $label;
    

    This will likely give a Can't find label ... error.

    Examples:

    sub func {
      my $x = shift;
      print "x = $x\n";
      my ($package, $file, $line) = caller();
      print "caller file: $file, line: $line\n";
    }
    
    sub foo {
      goto &func("from goto bar");
    }
    
    sub baz {
      return &func;
    }
    
    sub quux {
       goto &func;
    }
    
    baz("from baz");
    quux("from quux");
    foo("from foo");
    
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