Question

while (1)
{
    c = getchar();

    switch(state)
    {
      case 0:
          if((GPIO_ReadInputDataBit(GPIOA,GPIO_Pin_0) == Bit_SET))
          {
              state=1;
          }

          if ( c=='p')
          {
              state = 2;
          }
          break;

      case 1 :
          if((GPIO_ReadInputDataBit(GPIOA,GPIO_Pin_0) != Bit_SET))
          {
              state = 0;
          }
          break;

      case 2:
          iprintf("%s",led_name_arr[i]);
          if (c=='r')
          {
              state=0;
          }
          break;

    }
}

I want to print the printf and then reach state2 .. how can this be achieved .below is what i have tried and where i am stuck .

psuedocode:

if ( c==P)
{
  printf(" hi");
  state 2;
} 

** in this case the printf statement does not get executed **
or

case 2:
  iprintf("%s",led_name_arr[i]);
  if (c=='r')
  {
    state=0;
  }
  break;

** in this case the printf statement keeps printing in a loop **

i dont want the while loop to stop , in a continuous loop i want case 0 keeps working , but when it get the input p .. it pauses and executes the printf … and waits till it gets a r to resume case 0 …. Thus the program never halts but waits to either get “P” or “R” to execute each case… I hope i make sense

Any help will be appreciated .

Answer 1

i am not sure what you are asking but i m pretty sure what you want in case 2 is something like this:

case 2:
  iprintf("%s",led_name_arr[i]);
  while(c!='r')
  {
      c = getchar();
  }
  state=0;
  break;