Question

While googling how to convert a BIT (YESNO) column in an access database to a checkbox programmatically, a possible solution I found was to copy an existing database’s structure by using DoCmd.
I have added a reference to Microsoft.Office.Interop.Access and added those 2 lines in my code:

using Access = Microsoft.Office.Interop.Access;    
Access.Application myAccessInstance = new Access.Application();

In the try block where I open a connection to my database I’m executing Do.Cmd.TransferDatabase:

myAccessInstance.DoCmd.TransferDatabase(0, "Microsoft Access", "C:\\Users\\user\\Desktop\\Merge\\playlists.MDB", 0, "PlaylistNames",
                "PlaylistNamesCopy", true);

and I get a System.Runtime.InteropServices.COMException:

This operation requires an open database.

Does anyone know what is going wrong?

Answer 1

I do not know C#, so this is a rough example of how to set a field (column) in a table to a checkbox display, which is what I believe this question to be about.

//Added reference to COM Microsoft DAO 3.6

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            DAO.DBEngine dbEng = new DAO.DBEngine(); 
            DAO.Workspace ws = dbEng.CreateWorkspace("", "admin", "", DAO.WorkspaceTypeEnum.dbUseJet); 
            DAO.Database db = ws.OpenDatabase("z:\\docs\\dbfrom.mdb", false, false, "");
            DAO.TableDef tdf = db.TableDefs["Test"];

            DAO.Field fld = tdf.Fields["AYesNo"];
            //dbInteger  3 
            //accheckbox  106 
            DAO.Property prp = fld.CreateProperty("DisplayControl", 3,106);
            fld.Properties.Append(prp);
        }
    }
}