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Home/ Questions/Q 4569852
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T19:16:43+00:00 2026-05-21T19:16:43+00:00

while in visual c++ the code below is accepted, g++ will generate the error:

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while in visual c++ the code below is accepted, g++ will generate the error:
“class Derived does not have any field name Base”
which is following the standard?

template <class T>
class Base
{
public:
    Base(){};
};

template <class T>
class Derived:public Base<T>
{
public:
    Derived():Base(){}
};

BTW: both accept

Derived():Base<T>(){}

so meantime, I will follow gcc

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  1. Editorial Team
    Editorial Team
    2026-05-21T19:16:43+00:00Added an answer on May 21, 2026 at 7:16 pm

    MSVC++ is not correct. Base is a template, not a type.

    Note that in the usual case, Base is looked up in the scope of Derived<T>, which means that it will first find the injected class name inherited from Base<T>, which refers to the type Base<T>. But as you have a dependent base class, the name inherited from Base<T> is not found (the base class scope is not looked into).

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