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Home/ Questions/Q 500645
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:06:32+00:00 2026-05-13T06:06:32+00:00

while line = gets next if line =~ /^\s*#/ # skip comments break if

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while line = gets
   next if line =~ /^\s*#/    # skip comments
   break if line =~ /^END/   # stop at end

   #substitute stuff in backticks and try again
   redo if line.gsub!(/`(.*?)`/) { eval($1) } 

end

What I don’t understand is this line:

line.gsub!(/`(.*?)`/) { eval($1) }
  1. What does the gsub! exactly do?
  2. the meaning of regex (.*?)
  3. the meaning of the block {eval($1)}
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  1. Editorial Team
    Editorial Team
    2026-05-13T06:06:32+00:00Added an answer on May 13, 2026 at 6:06 am
    1. It will substitute within the matched part of line, the result of the block.
    2. It will match 0 or more of the previous subexpression (which was ‘.’, match any one char). The ? modifies the .* RE so that it matches no more than is necessary to continue matching subsequent RE elements. This is called “non-greedy”. Without the ?, the .* might also match the second backtick, depending on the rest of the line, and then the expression as a whole might fail.
    3. The block returns the result of eval (“evaluate a Ruby expression”) on the backreference, which is the part of the string between the back tick characters. This is specified by $1, which refers to the first paren-enclosed section (“backreference”) of the RE.

    In the big picture, the result of all this is that lines containing backtick-bracketed expressions have the part within the backticks (and the backticks) replaced with the result value of executing the contained Ruby expression. And since the outer block is subject to a redo, the loop will immediately repeat without rerunning the while condition. This means that the resulting expression is also subject to a backtick evaluation.

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