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Editorial Team
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Asked: 2026-05-13T18:35:32+00:00

While reading the Android guide to Notifications , I stumbled across this: Adding vibration

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While reading the Android guide to Notifications, I stumbled across this:

Adding vibration

You can alert the user with the the default vibration pattern or with a
vibration pattern defined by your application.

To use the default pattern, add “DEFAULT_VIBRATE” to the defaults field:

notification.defaults |= Notification.DEFAULT_VIBRATE;

What this does is clear: it adds the DEFAULT_VIBRATE flag to the default flags of the notification object.
But what does the |= operator do in Java?
It looks like an “OR”, but how does it work?

Can you provide an example using numbers?

Thanks

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1 Answer

  1. Editorial Team

    |= is a bitwise-OR-assignment operator. It takes the current value of the LHS, bitwise-ors the RHS, and assigns the value back to the LHS (in a similar fashion to += does with addition).

    For example:

    foo = 32;   // 32 =      0b00100000
bar = 9;    //  9 =      0b00001001
baz = 10;   // 10 =      0b00001010
foo |= bar; // 32 | 9  = 0b00101001 = 41
            // now foo = 41
foo |= baz; // 41 | 10 = 0b00101011 = 43
            // now foo = 43
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