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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T10:30:38+00:00 2026-05-12T10:30:38+00:00

While striving for const-correctness, I often find myself writing code such as this class

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While striving for const-correctness, I often find myself writing code such as this

class Bar;

class Foo {
public:
  const Bar* bar() const { /* code that gets a Bar somewhere */ }

  Bar* bar() {
    return const_cast< Bar* >(
      static_cast< const Foo* >(this)->bar());
  }
};

for lots of methods like bar(). Writing these non-const methods which call the const ones by hand is tedious; besides, I feel I am repeating myself – which makes me feel bad.

What can I do to alleviate this task? (Macros and code generators are not allowed.)

Edit: Besides litb’s solution I also like my own. 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T10:30:38+00:00Added an answer on May 12, 2026 at 10:30 am

    Another way could be to write a template that calls the function (using CRTP) and inherit from it.

    template<typename D>
    struct const_forward {
    protected:
      // forbid deletion through a base-class ptr
      ~const_forward() { }
    
      template<typename R, R const*(D::*pf)()const>
      R *use_const() {
        return const_cast<R *>( (static_cast<D const*>(this)->*pf)() );
      }
    
      template<typename R, R const&(D::*pf)()const>
      R &use_const() {
        return const_cast<R &>( (static_cast<D const*>(this)->*pf)() );
      }
    };
    
    class Bar;
    
    class Foo : public const_forward<Foo> {
    public:
      const Bar* bar() const { /* code that gets a Bar somewhere */ }
      Bar* bar() { return use_const<Bar, &Foo::bar>(); }
    };
    

    Note that the call has no performance lost: Since the member pointer is passed as a template parameter, the call can be inlined as usual.

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