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Home/ Questions/Q 7796327
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T23:20:30+00:00 2026-06-01T23:20:30+00:00

While trying to run the following snippet from Scala for the impatient : val

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While trying to run the following snippet from Scala for the impatient:

val b = ArrayBuffer(1,7,2,9)
val bSorted = b.sorted(_ < _)

I get the following error:

 error: missing parameter type for expanded function ((x$1, x$2) => x$1.$less(x$2))
       val bSorted = b.sorted(_ < _)

Can somebody explain what might be going on here. Shouldn’t the parameter type be inferred from the contents of the ArrayBuffer or do I need to specify it explicitly?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T23:20:31+00:00Added an answer on June 1, 2026 at 11:20 pm

    .sorted takes an implicit parameter of type Ordering (similar to Java Comparator). For integers, the compiler will provide the correct instance for you:

    scala> b.sorted
    res0: scala.collection.mutable.ArrayBuffer[Int] = ArrayBuffer(1, 2, 7, 9)
    

    If you want to pass a comparison function, use sortWith:

    scala> b.sortWith( _ < _ )
    res2: scala.collection.mutable.ArrayBuffer[Int] = ArrayBuffer(1, 2, 7, 9)
    
    scala> b.sortWith( _ > _ )
    res3: scala.collection.mutable.ArrayBuffer[Int] = ArrayBuffer(9, 7, 2, 1)
    

    However, pay attention, although ArrayBuffer is mutable, both sort methods will return a copy which is sorted, but the original won’t be touched.

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