Question

why "abc" + null results abcnull

String s1 = "abc";
String s2 = null; 
String s3 = s1+ s2;

System.out.println(s3);

Result: abcnull

Answer 1

Because Java will create a StringBuilder to append s1, or "abc", to s2, or null.

According to the spec for StringBuilder.append(String)–

If str is null, then the four characters "null" are appended

So it turns into the same as "abc" + "null"

Let’s take your code example (I placed it inside a method):

 public static void main(String[] args)
 {
  String s1 = "abc";
  String s2 = null; 
  String s3 = s1+ s2;
  System.out.println(s3);
 }

If we take a gander at the bytecode (gotten by invoking javap -c):

public static void main(java.lang.String[]);
  Code:
   0:   ldc #2; //String abc
   2:   astore_1
   3:   aconst_null
   4:   astore_2
   5:   new #3; //class java/lang/StringBuilder
   8:   dup
   9:   invokespecial   #4; //Method java/lang/StringBuilder."<init>":()V
   12:  aload_1
   13:  invokevirtual   #5; //Method java/lang/StringBuilder.append:(Ljava/lang/String;)Ljava/lang/StringBuilder;
   16:  aload_2
   17:  invokevirtual   #5; //Method java/lang/StringBuilder.append:(Ljava/lang/String;)Ljava/lang/StringBuilder;
   20:  invokevirtual   #6; //Method java/lang/StringBuilder.toString:()Ljava/lang/String;
   23:  astore_3
   24:  getstatic   #7; //Field java/lang/System.out:Ljava/io/PrintStream;
   27:  aload_3
   28:  invokevirtual   #8; //Method java/io/PrintStream.println:(Ljava/lang/String;)V
   31:  return

Java creates a StringBuilder and appends the values, as Strings, of s1 and s2.

So you have to be careful then, if you were expecting a NullPointerException, because concatenation in Java will skirt the issue.

Side Note: As pointed out by Jon Skeet, this is ultimately just implementation details — it’s the Java spec that guarantees that null, when converted to a String, turns into “null”. However, this bytecode at least shows what is actually happening behind the scenes.