Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Why can WinMain have two return types?
If I remove it,will report this warning:
warning C4007: 'WinMain' : must be '__stdcall'
Or I’m reading int WINAPI wrongly?
UPDATE
I tried these two variants which are said to be the same as WINAPI,none work:
int __declspec WinMain
int __declspec(stdcall) WinMain
WINAPIisn’t a return type it’s a macro expanding to an implementation specific decoration or attribute for the function. In this instance it specifies the calling convention and is equivalent to__stdcall.Grammatically, WINAPI is roughly (but not exactly) equivalent to a storage class specifier like
static.