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Home/ Questions/Q 8599707
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T01:27:16+00:00 2026-06-12T01:27:16+00:00

Why can’t you declare a 2D array argument in a function as you do

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Why can’t you declare a 2D array argument in a function as you do with a normal array?

 void F(int bar[]){} //Ok
 void Fo(int bar[][]) //Not ok
 void Foo(int bar[][SIZE]) //Ok

Why is it needed to declare the size for the column?

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  1. Editorial Team
    Editorial Team
    2026-06-12T01:27:17+00:00Added an answer on June 12, 2026 at 1:27 am

    You can’t write void Foo(int bar[][]), because bar decays to a pointer. Imagine following code:

    void Foo(int bar[][]) // pseudocode
    {
        bar++; // compiler can't know by how much increase the pointer
        // as it doesn't know size of *bar
    }
    

    So, compiler must know size of *bar, therefore size of rightmost array must be provided.

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