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Home/ Questions/Q 6965733
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T16:05:58+00:00 2026-05-27T16:05:58+00:00

Why do I get a different output with $key++ and $key+1 ? What should

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Why do I get a different output with $key++ and $key+1?

What should I do to refer to the next element in the loop using foreach?

foreach($diff as $key=>$val) {

if(in_array($diff[$key],$common) && in_array($diff[$key+1],$common)) {}

if(in_array($diff[$key],$common) && in_array($diff[$key++],$common)) {}

}
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  1. Editorial Team
    Editorial Team
    2026-05-27T16:05:59+00:00Added an answer on May 27, 2026 at 4:05 pm

    $x++ returns the old value of $x (before the increment). For example, $x=3; print $x++; will print “3”. It also modifies $x, so it’s not the best choice unless that’s your intent. (Here, incrementing would be pretty useless, particularly since the modified keys never see the outside of the loop.)

    ++$x would return the new value of $x. Like $x++, though, it’s semantically wrong for just getting the next number, as it modifies $x.

    Just stick with $x + 1.

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