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Home/ Questions/Q 8613645
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T04:55:48+00:00 2026-06-12T04:55:48+00:00

Why do I get this result at the REPL? >>> a = [1, 2,

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Why do I get this result at the REPL?

>>> a = [1, 2, 3]
>>> b = a
>>> b is a
True

My understanding is that is only evaluates to True if the two variables point to the same object, when in this case they’re different objects with the same value. == would evaluate to True, but is shouldn’t.

Going further:

>>> b.reverse()
>>> (a, b)
([3, 2, 1], [3, 2, 1])

It seems that as far as the interpreter is concerned, they are the same object, and operations on b will automatically be performed on a. Again, why?

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  1. Editorial Team
    Editorial Team
    2026-06-12T04:55:49+00:00Added an answer on June 12, 2026 at 4:55 am

    When you do a = [1, 2, 3] you’re binding the name a to a list object. When you do b = a, you’re binding the name b to whatever a is – in this case the list object. Ergo, they’re the same… An object can have multiple names. It’s worth reading up on the Python Data Model.

    If you wanted to make a copy of your listobj, then you can look at b = a[:] to use slice to create a shallow copy, or copy.copy for a shallow copy (should work on arbitary objects), or copy.deepcopy for strangely – a deep copy.

    You’ll also notice something surprising in CPython which caches short strings/small integers…

    >>> a = 4534534
    >>> b = a
    >>> a is b
    True
    >>> b = 4534534
    >>> a is b
    False
    >>> a = 1
    >>> b = a
    >>> a is b
    True
    >>> b = 1
    >>> a is b
    True
    
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