Question

 

Why does calling 152..toString(2) return a binary string value of "10011000", when a call to 152.toString(2) throws the following exception?

          "SyntaxError: identifier starts immediately after numeric literal"

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It seems to me that it’s intuitive to want to use the latter call to toString(), as it looks & feels correct. The first example just seems plain odd to me.

Does anyone know why JavaScript was designed to behave like this?

Answer 1

A . after a number might seem ambiguous. Is it a decimal or an object member operator?

However, the interpreter decides that it’s a decimal, so you’re missing the member operator.

It sees it as this:

(10.)toString();  // invalid syntax

When you include the second ., you have a decimal followed by the member operator.

(10.).toString();

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@pedants and downvoters

The . character presents an ambiguity. It can be understood to be the member operator, or a decimal, depending on its placement. If there was no ambiguity, there would be no question to ask.

The specification’s interpretation of the . character in that particular position is that it will be a decimal. This is defined by the numeric literal syntax of ECMAScript.

Just because the specification resolves the ambiguity for the JS interpreter, doesn’t mean that the ambiguity of the . character doesn’t exist at all.