Why does the code below work without any crash @ runtime ?
And also the size is completely dependent on machine/platform/compiler!!. I can even give upto 200 in a 64-bit machine. how would a segmentation fault in main function get detected in the OS?
int main(int argc, char* argv[])
{
int arr[3];
arr[4] = 99;
}
Where does this buffer space come from? Is this the stack allocated to a process ?
Something I wrote sometime ago for education-purposes…
Consider the following c-program:
after compiling it and executing it, a core dump is produced:
now using gdb to perform a post mortem analysis:
huh, the program didn’t segfault when one wrote outside the 200 items allocated, instead it crashed when i=1008, why?
Enter pages.
One can determine the page size in several ways on UNIX/Linux, one way is to use the system function sysconf() like this:
which gives the output:
or one can use the commandline utility getconf like this:
post mortem
It turns out that the segfault occurs not at i=200 but at i=1008, lets figure out why. Start gdb to do some post mortem ananlysis:
q ended at at address 0x804a35c, or rather, the last byte of q[199] was at that location. The page size is as we saw earlier 4096 bytes and the 32-bit word size of the machine gives that an virtual address breaks down into a 20-bit page number and a 12-bit offset.
q[] ended in virtual page number:
0x804a = 32842
offset:
0x35c = 860
so there were still:
4096 – 864 = 3232
bytes left on that page of memory on which q[] was allocated. That space can hold:
3232 / 4 = 808
integers, and the code treated it as if it contained elements of q at position 200 to 1008.
We all know that those elements don’t exists and the compiler didn’t complain, neither did the hw since we have write permissions to that page. Only when i=1008 did q[] refer to an address on a different page for which we didn’t have write permission, the virtual memory hw detected this and triggered a segfault.
An integer is stored in 4 bytes, meaning that this page contains 808 (3236/4) additional fake elements meaning that it is still perfectly legal to access these elements from q[200], q[201] all the way up to element 199+808=1007 (q[1007]) without triggering a seg fault. When accessing q[1008] you enter a new page for which the permission are different.