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Home/ Questions/Q 746417
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T14:05:19+00:00 2026-05-14T14:05:19+00:00

Why does the following code fail to compile, while changing the case statement to

  • 0

Why does the following code fail to compile, while changing the case statement to

case ENUM1: doSomeStuff();

works?

public enum EnumType
{
    ENUM1, ENUM2, ENUM3;

    void doSomeStuff()
    {
        switch(this)
        {
        case EnumType.ENUM1: doSomeStuff();
        }
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-14T14:05:19+00:00Added an answer on May 14, 2026 at 2:05 pm

    This is to avoid the ability to compare against different enum types. It makes sense to restrict it to one type, i.e. the type of the enum value in the switch statement.

    Update: it’s actually to keep binary compatibility. Here’s a cite from about halfway chapter 13.4.9 of JLS:

    One reason for requiring inlining of constants is that switch statements require constants on each case, and no two such constant values may be the same. The compiler checks for duplicate constant values in a switch statement at compile time; the class file format does not do symbolic linkage of case values.

    In other words, because of the class identifier in EnumType.ENUM1, it cannot be represented as a compiletime constant expression, while it is required by the switch statement.

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