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Why does the following code output 1, instead of 0? a || b should give me 1 and 1 && 0 is 0, right? I don’t think logical operations evaluated from right to left.
int main()
{
printf("%d\n", 1 || 1 && 0);
return 0;
}
&&has higher precedence than||. (Like how multiplication has higher precedence than addition.)