Question

Why does the following code print “?” ?
Also how can -1 be assigned to an unsigned char?

char test;
unsigned char testu; //isn't it supposed to hold values in range 0 - 255?
test = -1;
testu = -1;
cout<<"TEST CHAR = "<<test<<endl;
cout<<"TESTU CHAR = "<<testu<<endl;

Answer 1

unsigned simply affects how the internal representation of the number (chars are numbers, remember) is interpreted. So -1 is 1111 1111 in two’s complement notation, which when put into an unsigned char changes the meaning (for the same bit representation) to 255.

The question mark is probably the result of your font/codepage not mapping the (extended) ASCII value 255 to a character it can display.

I don’t think << discerns between an unsigned char and a signed char, since it interprets their values as ASCII codes, not plain numbers.

Also, it depends on your compiler whether chars are signed or unsigned by default; actually, the spec states there’s three different char types (plain, signed, and unsigned).