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Home/ Questions/Q 1061659
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T18:30:22+00:00 2026-05-16T18:30:22+00:00

Why does the following compile in C++? int phew = 53; ++++++++++phew ; The

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Why does the following compile in C++?

int phew = 53;
++++++++++phew ;

The same code fails in C, why?

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  1. Editorial Team
    Editorial Team
    2026-05-16T18:30:23+00:00Added an answer on May 16, 2026 at 6:30 pm

    That is because in C++ pre-increment operator returns an lvalue and it requires its operand to be an lvalue.

    ++++++++++phew ; in interpreted as ++(++(++(++(++phew))))

    However your code invokes Undefined Behaviour because you are trying to modify the value of phew more than once between two sequence points.

    In C, pre-increment operator returns an rvalue and requires its operand to be an lvalue. So your code doesn’t compile in C mode.

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