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Home/ Questions/Q 668015
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:59:36+00:00 2026-05-13T23:59:36+00:00

why does the following js expression: test1 foo bar test2.replace(/foo.bar/, $’) result in the

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why does the following js expression:

"test1 foo bar test2".replace(/foo.bar/, "$'")

result in the following string?

"test1  test2 test2"

is the $' in the replace string some sort of control code for including everything after the match???

this behavior was screwing with me most of the day. can anyone explain this?

thanks a lot

ps- this is the case in all browsers i’ve tested

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:59:36+00:00Added an answer on May 13, 2026 at 11:59 pm

    In a regex replace parameter, you need to escape the $:

    "test1 foo bar test2".replace(/foo.bar/, "$$'")
    

    $' inserts the portion of the string that follows the matched substring.
    See the documentation.

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