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Home/ Questions/Q 6190113
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T02:31:45+00:00 2026-05-24T02:31:45+00:00

Why does the following print 1 . I was expecting it to print the

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Why does the following print 1. I was expecting it to print the address of the function pointer.

#include <stdio.h>

int main(main) {
  printf("%i",main);
  return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-05-24T02:31:47+00:00Added an answer on May 24, 2026 at 2:31 am

    Pointers must be printed with %p. Anyway here there’s an “aliasing” problem, rather odd but that’s it: main gets the value of the first argument to function main that is, what usually is called “argc”. if you call it with more arguments, you should see bigger number.

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