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Home/ Questions/Q 6223797
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T08:33:05+00:00 2026-05-24T08:33:05+00:00

Why does the transposed matrix look differently, when converted to a pycuda.gpuarray ? Can

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Why does the transposed matrix look differently, when converted to a pycuda.gpuarray?

Can you reproduce this? What could cause this? Am I using the wrong approach?

Example code

from pycuda import gpuarray
import pycuda.autoinit
import numpy

data = numpy.random.randn(2,4).astype(numpy.float32)
data_gpu = gpuarray.to_gpu(data.T)
print "data\n",data
print "data_gpu.get()\n",data_gpu.get()
print "data.T\n",data.T

Output

data
[[ 0.70442784  0.08845157 -0.84840715 -1.81618035]
 [ 0.55292499  0.54911566  0.54672164  0.05098847]]
data_gpu.get()
[[ 0.70442784  0.08845157]
 [-0.84840715 -1.81618035]
 [ 0.55292499  0.54911566]
 [ 0.54672164  0.05098847]]
data.T
[[ 0.70442784  0.55292499]
 [ 0.08845157  0.54911566]
 [-0.84840715  0.54672164]
 [-1.81618035  0.05098847]]
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  1. Editorial Team
    Editorial Team
    2026-05-24T08:33:05+00:00Added an answer on May 24, 2026 at 8:33 am

    The basic reason is that numpy transpose only creates a view, which has no effect on the underlying array storage, and it is that storage which PyCUDA directly accesses when a copy is performed to device memory. The solution is to use the copy method when doing the transpose, which will create an array with data in the transposed order in host memory, then copy that to the device:

    data_gpu = gpuarray.to_gpu(data.T.copy())
    
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