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Home/ Questions/Q 660183
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:07:40+00:00 2026-05-13T23:07:40+00:00

Why does this code always return 0? var possibleMatches = new Array(); $.getJSON(‘getInformation.php’, function(data)

  • 0

Why does this code always return 0?

     var possibleMatches = new Array();
  $.getJSON('getInformation.php', function(data) {
   $.each(data, function(i){
    possibleMatches.push(data[i]);
   })
  });
  alert(possibleMatches.length);

Though I can move or add “alert(possibleMatches.length);” inside the $.each and it will output the correct number of elements.

I’m just curious as to why it the values aren’t going into the array as I expected. I’m sure its a local variable vs. global variable issue, just not sure why.

Basically, what this is trying to do is fill the possibleMatches array with the data results.

thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:07:41+00:00Added an answer on May 13, 2026 at 11:07 pm

    Asynchronicity. The line alert(possibleMatches.length); executes before the success callback for $.getJSON() executes.

    So, to have your alert report accurately, just move it.

    var possibleMatches = new Array();
    $.getJSON('getInformation.php', function(data) {
      $.each(data, function(i){
        possibleMatches.push(data[i]);
      })
    
      // To here
      alert(possibleMatches.length);
    });
    // From here
    

    Remember, the first A in AJAX stands for “Asynchronous”

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