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Home/ Questions/Q 8965409
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T16:47:45+00:00 2026-06-15T16:47:45+00:00

Why does this code fragment: if (iErr) { std::stringstream ss; string serror(error); ss <<

  • 0

Why does this code fragment:

 if (iErr) {
    std::stringstream ss;
    string serror("error");
    ss << "lua error code " << iErr << ": " << lua_tostring(lua, -1);
    ss >> serror;

    Log *log= StandardLog::getInstance();
    log->logError("Lua error following in next line");
    log->logError(serror);

    //lua_pop(lua, 1);/* pop error message from the stack */
    return 1;
 }

just print:

Lua error following in next line
lua

instead of

Lua error following in next line
lua error code 3: lua/generator/generator_example_nodenavigator.lua:10: attempt to call global 'require' (a nil value)

The Logger lines look like this:

void Logger::log(char message[]){
    string smessage(message);
    log(smessage);
}

void Logger::log(string smessage){
    ...
}

but it appears the logger is not at fault, since i get the same output using cerr.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T16:47:46+00:00Added an answer on June 15, 2026 at 4:47 pm

    The input operator >> extracts only until the next whitespace. Either use std::getline or the stringstream::str function to get the string.

    My recommendation is to change to std::ostringstream and use std::ostringstream::str:

    std::ostringstream oss;
    
    oss << "lua error code " << iErr << ": " << lua_tostring(lua, -1);
    
    Log *log= StandardLog::getInstance();
    log->logError("Lua error following in next line");
    log->logError(oss.str());
    
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