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Home/ Questions/Q 6979637
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T17:54:43+00:00 2026-05-27T17:54:43+00:00

Why does this code segment give segmentation fault? #include <stdio.h> #include <stdlib.h> #include <sys/mman.h>

  • 0

Why does this code segment give segmentation fault?

#include <stdio.h>
#include <stdlib.h>
#include <sys/mman.h>
#include <string.h>

int main()
{
    void *ptr;

    ptr=mmap(NULL, 10, PROT_READ|PROT_WRITE, MAP_ANONYMOUS, -1, 0);
    strcpy(ptr, "Hello");

}

Or better, i would like to have: char *ptr=malloc(10); then pass this argument to mmap. Both gives SIGSEGV.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T17:54:43+00:00Added an answer on May 27, 2026 at 5:54 pm

    Check the return values of your system calls!

    The flags argument to mmap must have exactly one of these two options:

    MAP_SHARED
      Share  this mapping.  Updates to the mapping are visible to other processes
      that map this file, and are carried through to the underlying file. The file
      may not actually  be updated until msync(2) or munmap() is called.
    
    MAP_PRIVATE
      Create  a private copy-on-write mapping.  Updates to the mapping are not
      visible to other processes mapping the same file, and are not carried through
      to the underlying file.   It is  unspecified whether changes made to the file
      after the mmap() call are visible in the mapped region.
    

    You’re not providing that, so mmap is most likely failing (returning (void*)-1) with errno set to EINVAL.

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