Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 918093
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T18:18:55+00:00 2026-05-15T18:18:55+00:00

Why does this code (taken from the demo sample at jquery ui), doesn’t work

  • 0

Why does this code (taken from the demo sample at jquery ui), doesn’t work for me? It says .button() is not a function.

Update: Tried loading from google no luck. Here is teh error

$(“.demo button:first”).button is not a function

Line 27

http://pastie.org/1039784

 <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
    <meta http-equiv="Content-type" content="text/html; charset=utf-8" />
    <title>Page Title</title>
    <link rel="stylesheet" href="screen.css" type="text/css" media="screen" title="no title" charset="utf-8" />
    <link rel="stylesheet" href="scripts/css/ui-lightness/jquery-ui-1.8.2.custom.css" type="text/css" media="screen" title="no title" charset="utf-8" />


    <script type="text/javascript" src="http://www.google.com/jsapi"></script>
<script type="text/javascript"> 
    google.load("jquery", "1.3.2");
    google.load("jqueryui", "1.7.2");
</script>


</head>
<body>
    <div id="container" class="container">

    <script type="text/javascript">
        $(document).ready(function(){
                $(".demo button:first").button({
            icons: {
                primary: 'ui-icon-locked'
            },
            text: false
        }).next().button({
            icons: {
                primary: 'ui-icon-locked'
            }
        }).next().button({
            icons: {
                primary: 'ui-icon-gear',
                secondary: 'ui-icon-triangle-1-s'
            }
        }).next().button({
            icons: {
                primary: 'ui-icon-gear',
                secondary: 'ui-icon-triangle-1-s'
            },
            text: false
        });

        });
    </script>


<div class="demo">

    <button>Button with icon only</button>
    <button>Button with icon on the left</button>
    <button>Button with two icons</button>
    <button>Button with two icons and no text</button>

</div><!-- End demo -->

    <div>
        <ul>
            <li>
                <a id="icon_only"></a>
            </li>
        </ul>
    </div>
    </div>              

</body>
</html>
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T18:18:56+00:00Added an answer on May 15, 2026 at 6:18 pm

    looks like your route to jquery may be wrong, try this:

    <script type="text/javascript" src="http://www.google.com/jsapi"></script>
    <script type="text/javascript"> 
        google.load("jquery", "1.3.2");
        google.load("jqueryui", "1.7.2");
    </script>
    

    that should load the jquery and jquery ui libs from google servers and this way it should work fine

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 536k
  • Answers 536k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer You can repeat a css background image but you can't… May 17, 2026 at 1:18 am
  • Editorial Team
    Editorial Team added an answer From the MSSQL documentation: "GO is not a Transact-SQL statement;… May 17, 2026 at 1:18 am
  • Editorial Team
    Editorial Team added an answer You need to do the following Change: foreach ($mob as… May 17, 2026 at 1:18 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Related Questions

Why do the code snippets below, taken from this article , produce different results
The code below is more or less taken from the example MPMoviePlayerController sample code.
Possible Duplicate: Can someone Explain this jQuery code? I have posted this before, but
For this code: #include<stdio.h> void hello() { printf(hello\n); } void bye() { printf(bye\n); }
i created a carousel in jquery that slides an item or set of items
I am working on a PHP code for my social network, what I am
see the following code: void simple_dynamic_casts( ) { AB ab; B* bp = (B*)&ab;
I am having trouble using the character é in a returned column name from
I have seen a similar line of code floating about in Apples code: (void)[[URLRequest
I've made a bundle module which does a bunch of things: imports Moose ,

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.