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Editorial Team
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Asked: 2026-06-19T00:38:41+00:00

Why does this code throw a NumberFormatException : String binStr = 1000000000000000000000000000000000000000000000000000000000000000; System.out.println(binStr.length());// =

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Why does this code throw a NumberFormatException : 

String binStr = "1000000000000000000000000000000000000000000000000000000000000000";
System.out.println(binStr.length());// =  64
System.out.println(Long.parseLong(binStr, 2));
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  1. Editorial Team

    1000000000000000000000000000000000000000000000000000000000000000 is larger than Long.MAX_VALUE.

    See https://stackoverflow.com/a/8888969/597657

    Consider using BigInteger(String val, int radix) instead.

    EDIT:

    OK, this is new for me. It appears that Integer.parseInt(binaryIntegerString, 2) and Long.parseLong(binaryLongString, 2) parse binary as sign-magnitude not as a 2’s-complement.

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