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Home/ Questions/Q 4014326
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Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T09:29:00+00:00 2026-05-20T09:29:00+00:00

Why does this work: a = [] a.push([‘test’]); (function() {alert(‘poop’)})() But this gives the

  • 0

Why does this work:

a = []
a.push(['test']);
(function() {alert('poop')})()

But this gives the error “number is not a function”:

a = []
a.push(['test'])
(function() {alert('poop')})()

The only difference is the semicolon at the end of line 2. I’ve been writing JavaScript for a long time now. I know about automatic semicolon insertion, but I can’t figure out what would be causing this error.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T09:29:01+00:00Added an answer on May 20, 2026 at 9:29 am

    Take a look at this example of chained function calls.

    a.push(['test'])(function() {alert('poop')})()
    

    Look familiar? This is how the compiler/interpreter views your code.

    Detail

    Here is a portion of the grammar used to describe call expressions.

    CallExpression : 
    	MemberExpression Arguments 
    	CallExpression Arguments 
    	CallExpression [ Expression ] 
    	CallExpression . IdentifierName 
    

    Essentially each group (…) is considered as Arguments to the original MemberExpression a.push.

    a.push (['test'])                // MemberExpression Arguments 
    (function() {alert('poop')})     // Arguments  
    ()                               // Arguments 
    

    Or more formally

    CallExpression(
        CallExpression(  
            CallExpression(
                MemberExpression( a.push ),
                Arguments( (['test']) )
            ),
            Arguments( (function() {alert('poop')}) )
        ),
        Arguments( () )
    )
    
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