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Home/ Questions/Q 808199
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T00:31:29+00:00 2026-05-15T00:31:29+00:00

Why does this work: function myfunction($v) { $query = $v[‘host’] == ‘1’; return (

  • 0

Why does this work:

function myfunction($v) {
    $query = $v['host'] == '1';
    return ( $query );
}

$output = array_filter($recordset,myfunction);
print_r($output);

Whereas this script, which tries to accomplish the same thing with variables, does not?

$column1 = 'host';
$value1 = 1;
$query1 = '$v[\''.$column1.'\'] == '.$value1;

function myfunction($v) {
    $query = $GLOBALS['query1'];
    return ( $query );
}

$output = array_filter($recordset,myfunction);
print_r($output);

Any help would be great. Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T00:31:30+00:00Added an answer on May 15, 2026 at 12:31 am

    The statement $query = $v['host'] == '1'; doesn’t set $query to be the expression $v['host'] == '1'. It evaluates $v['host'] == '1' and sets $query to the value of the expression, which is 1 or 0, depending on whether $v['host'] is equal to '1'.

    $output = array_filter($recordset,myfunction); works because array_filter is meant to take a user-defined PHP callback function for its second argument.

    Dynamic coding is really only achievable in PHP using the eval function (highly dangerous!) or using an object-oriented structure with object overloading.

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