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Home/ Questions/Q 6329813
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T17:44:50+00:00 2026-05-24T17:44:50+00:00

Why does this work: //split returns (char**) char *temp2; temp2=split(array[i],’=’)[1]; and this doesn’t: char

  • 0

Why does this work:

    //split returns (char**)
    char *temp2;
    temp2=split(array[i],'=')[1];

and this doesn’t:

char **temps;
temps[0]=temp2; //crashes

or this:

temps[0]=split(array[i],'=')[1]; //crashes
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  1. Editorial Team
    Editorial Team
    2026-05-24T17:44:50+00:00Added an answer on May 24, 2026 at 5:44 pm

    temps is just a pointer to a char*, but it has no initalized, sensible value! temps[0] is equivalent to *(temps + 0), but you cannot dereference a garbage value — you first have to make temps points somewhere useful, e.g. by allocating memory for it.

    If you want to store some char*s with automatic storage, then declare an array of char pointers instead:

    char * temps[20];
    temps[0] = /*... etc. ...*/
    
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