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Home/ Questions/Q 4012842
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T09:17:51+00:00 2026-05-20T09:17:51+00:00

Why doesn’t Ctrl + C work to break a Python program that uses PyQt?

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Why doesn’t Ctrl+C work to break a Python program that uses PyQt? I want to debug it and get a stack trace and for some reason, this is harder to do than with C++!

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  1. Editorial Team
    Editorial Team
    2026-05-20T09:17:52+00:00Added an answer on May 20, 2026 at 9:17 am

    CTRL+C causes a signal to be sent to
    the process. Python catches the
    signal, and sets a global variable,
    something like CTRL_C_PRESSED = True.
    Then, whenever the Python interpreter
    gets to execute a new opcode, it sees
    the variable set and raises a
    KeybordInterrupt.

    This means that CTRL+C works only if
    the Python interpreter is spinning. If
    the interpreter is executing an
    extension module written in C that
    executes a long-running operation,
    CTRL+C won’t interrupt it, unless it
    explicitly “cooperates” with Python.
    Eg: time.sleep() is theoretically a
    blocking operation, but the
    implementation of that function
    “cooperates” with the Python
    interpreter to make CTRL+C work.

    This is all by design: CTRL+C is meant
    to do a “clean abort”; this is why it
    gets turned into an exception by
    Python (so that the cleanups are
    executed during stack unwind), and its
    support by extension modules is sort
    of “opt-in”. If you want to totally
    abort the process, without giving it a
    chance to cleanup, you can use CTRL+.

    When Python calls QApplication::exec()
    (the C++ function), Qt doesn’t know
    how to “cooperate” with Python for
    CTRL+C, and this is why it does not
    work. I don’t think there’s a good way
    to “make it work”; you may want to see
    if you can handle it through a global
    event filter.
    — Giovanni Bajo

    Adding this to the main program solved the problem.

    import signal
    
    signal.signal(signal.SIGINT, signal.SIG_DFL)
    

    I’m not sure what this has to do with the explanation.

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