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Home/ Questions/Q 6791493
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T17:51:11+00:00 2026-05-26T17:51:11+00:00

Why doesn’t the C# compiler tell me that this piece of code is invalid?

  • 0

Why doesn’t the C# compiler tell me that this piece of code is invalid?

class Program
{
    static void Main(string[] args)
    {
        dynamic d = 1;
        MyMethod(d);
    }

    public void MyMethod(int i) 
    {
        Console.WriteLine("int");
    }
}

The call to MyMethod fails at runtime because I am trying to call a non-static method from a static method. That is very reasonable, but why doesn’t the compiler consider this an error at compile time?

The following will not compile

class Program
{
    static void Main(string[] args)
    {
        dynamic d = 1;
        MyMethod(d);
    }
}

so despite the dynamic dispatch, the compiler does check that MyMethod exists. Why doesn’t it verify the “staticness”?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T17:51:12+00:00Added an answer on May 26, 2026 at 5:51 pm

    Overload resolution is dynamic here. Visible in this code snippet:

    class Program {
        public static void Main() {
            dynamic d = 1.0;
            MyMethod(d);
        }
    
        public void MyMethod(int i) {
            Console.WriteLine("int");
        }
    
        public static void MyMethod(double d) {
            Console.WriteLine("double");
        }
    }
    

    Works fine. Now assign 1 to d and note the runtime failure. The compiler cannot reasonably emulate dynamic overload resolution at compile time, so it doesn’t try.

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