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Home/ Questions/Q 7435645
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T10:06:34+00:00 2026-05-29T10:06:34+00:00

Why doesn’t this work? type RetryBuilder(max) = member x.Return(a) = a // Enable ‘return’

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Why doesn’t this work?

type RetryBuilder(max) = 
  member x.Return(a) = a               // Enable 'return'
  member x.Delay(f) = f                // Gets wrapped body and returns it (as it is)
                                       // so that the body is passed to 'Run'
  member x.Zero() = failwith "Zero"    // Support if .. then 
  member x.Run(f) =                    // Gets function created by 'Delay'
    let rec loop 0 (Some(ex)) = raise ex
    let rec loop n maybeEx    = try f() with ex -> loop (n-1) (Some(ex))
    loop max None

let retry = RetryBuilder(4)

It says ‘incomplete pattern matches on this expression. For example, the value ‘1’ may indicate a case not covered by the pattern’.

But why wouldn’t that match the one below? If I remember correctly, Haskell would match that, why doesn’t F#?

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  1. Editorial Team
    Editorial Team
    2026-05-29T10:06:35+00:00Added an answer on May 29, 2026 at 10:06 am

    You’re writing F# code in Haskell syntax. The reason why your code compiles is F# compiler thought there are two loop functions where the former is shadowed by the latter. Obviously in the first loop function, pattern matching fails with any integer different from 0 for the first parameter and None for the second parameter.

    A declaration close to Haskell syntax could be:

    let rec loop = function 
        | 0, Some ex -> raise ex
        | n, maybeEx -> try f() with ex -> loop (n-1, Some ex)
    loop(max, None)
    
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