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Home/ Questions/Q 8667433
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T17:57:44+00:00 2026-06-12T17:57:44+00:00

why following code throwing ConcurrentModificationException? Josh Bloch can avoid ConcurrentModificationException. ArrayList<Integer> list=new ArrayList<Integer>(); list.add(100);

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why following code throwing ConcurrentModificationException? Josh Bloch can avoid ConcurrentModificationException.

ArrayList<Integer> list=new ArrayList<Integer>();
list.add(100);
list.add(200);
list.add(300);
list.add(400);
for(Integer field : list) {    
    list.remove(field);
    list.add(200);
}       
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  1. Editorial Team
    Editorial Team
    2026-06-12T17:57:45+00:00Added an answer on June 12, 2026 at 5:57 pm

    You can’t use remove on the list while using the “for each” loop. Instead, you can use this to call remove on the iterator:

    Iterator<Integer> iterator = list.iterator();
    while(iterator.hasNext()) {
        Integer integer = iterator.next();
    
        // ...check if you want to remove this one...
    
        iterator.remove();
    }
    

    If you actually want to replace every value with “200”, or replace with some other value, it might make more sense to build up a new list:

    List<Integer> newList = new ArrayList<Integer>();
    
    Iterator<Integer> iterator = list.iterator();
    while(iterator.hasNext()) {
        Integer integer = iterator.next();
    
        newList.add(integer);
    
        iterator.remove();
    }
    
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