Question

Why if (var) … uses number conversion instead of boolean ?
I have a class that implements both :

operator int() { ....}
operator bool() { ....}

but if I use :

if (my_class_var) ....;

then the int conversion is used instead of boolean ?!!?!

EDIT:
As versedmarald say it is correct. I found what was the differnce.. I’m in fact using :

operator int() { ....}
operator bool() const { ... }

Still mesmerized, why the difference ?
gcc version 4.6.2

Answer 1

It doesn’t (using g++ at least). My guess would be there is an error in your conversion operators.

#include <iostream>
class A {
public:
    operator int() { return 1; }
};

class B {
public:
    operator int() { return 1; }
    operator bool() { return false; }
};

int main() {
    A a;
    B b;

    if (a)
        std::cout << "true\n";
    else
        std::cout << "false\n";

    if (b)
        std::cout << "true\n";
    else
        std::cout << "false\n";
}

Outputs:

true
false