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Home/ Questions/Q 724885
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:16:28+00:00 2026-05-14T06:16:28+00:00

Why in this example from MSDN, in GetEnumerator method, PeopleEnum returns IEnumerator ? public

  • 0

Why in this example from MSDN, in GetEnumerator method, PeopleEnum returns IEnumerator?

public class Person
{
    public Person(string fName, string lName)
    {
        this.firstName = fName;
        this.lastName = lName;
    }

    public string firstName;
    public string lastName;
}

public class People : IEnumerable
{
    private Person[] _people;
    public People(Person[] pArray)
    {
        _people = new Person[pArray.Length];

        for (int i = 0; i < pArray.Length; i++)
        {
            _people[i] = pArray[i];
        }
    }
   //why??? 
   IEnumerator IEnumerable.GetEnumerator()
   {
       return (IEnumerator) GetEnumerator();
   }

   public PeopleEnum GetEnumerator()
   {
       return new PeopleEnum(_people);
   }
}

public class PeopleEnum : IEnumerator
{
    public Person[] _people;

// Enumerators are positioned before the first element
// until the first MoveNext() call.
int position = -1;

public PeopleEnum(Person[] list)
{
    _people = list;
}

public bool MoveNext()
{
    position++;
    return (position < _people.Length);
}

public void Reset()
{
    position = -1;
}

object IEnumerator.Current
{
    get
    {
        return Current;
    }
}

public Person Current
{
    get
    {
        try
        {
            return _people[position];
        }
        catch (IndexOutOfRangeException)
        {
            throw new InvalidOperationException();
        }
    }
}

UPDATE:
BTW, if Array data type implements ICloneable interface, why msdn has copied pArray to _people by writing a for loop?

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:16:28+00:00Added an answer on May 14, 2026 at 6:16 am

    It needs to return exactly IEnumerator to properly implement the IEnumerable interface. It is doing this using an “explicit interface implementation”, so on the public API you see PeopleEnum, but IEnumerable is still happy

    But in reality you would very rarely write an enumerator this way in C# 2.0 or above; you’d use an iterator block (yield return). See C# in Depth chapter 6 (free chapter!).

    For info, the reason that PeopleEnum exists at all here is that this looks like a .NET 1.1 sample, where that is the only way to create a typed enumerator. In .NET 2.0 and above there is IEnumerable<T> / IEnumerator<T>, which has a typed (via generics) .Current.

    In .NET 2.0 / C# 2.0 (or above) I would have simply:

    public class People : IEnumerable<Person> {
        /* snip */
        public IEnumerator<Person> GetEnumerator() {
            return ((IEnumerable<Person>)_people).GetEnumerator();
        }
        IEnumerator IEnumerable.GetEnumerator() { return _people.GetEnumerator();}
    }
    
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