Why is int i = 2147483647 + 1; OK, but byte b = 127 + 1; is not compilable?
Why is int i = 2147483647 + 1; OK, but byte b = 127
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Constants are evaluated as ints, so
2147483647 + 1overflows and gives you a new int, which is assignable toint, while127 + 1also evaluated asintequals to128, and it is not assignable tobyte.