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Home/ Questions/Q 1082025
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T22:14:40+00:00 2026-05-16T22:14:40+00:00

Why is it that the Common Lisp array syntax is not evaluating its arguments:

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Why is it that the Common Lisp array syntax is not evaluating its arguments:

(let ((a 1)) #2A((a 2) (3 4)))
=> #2A((A 2) (3 4))

I would have guessed it was #2A((1 2) (3 4)). Is this because A is not available at reader time?

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  1. Editorial Team
    Editorial Team
    2026-05-16T22:14:40+00:00Added an answer on May 16, 2026 at 10:14 pm

    In short, yes.

    #2A((A 2) (3 4)) is not an abbreviation (“syntactic sugar”) for (make-array '(2 2) :initial-contents (list (list a 2) (list 3 4))). If anything, it could be rationalized as (make-array '(2 2) :initial-contents (quote ((A 2) (3 4)))), but this would be a bit misleading as the array construction already happens at read-time.

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