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Home/ Questions/Q 4381856
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T12:42:12+00:00 2026-05-21T12:42:12+00:00

Why is it that you can only create a pionter to an inner class

  • 0

Why is it that you can only create a pionter to an inner class as a member of the enclosing class.
How is it aranged in memory and why does it prevent this, ex:

class temp  
{  
    public:

    class inner
    {
    public:
        inner(int a = 0) : memberInt(a) {}
        const int memberInt;
    };

    temp(int i = 0) : member(i)  
    {  
    }  
    inner *i; // this works  
    inner i; // this doesn't  
    int member;  
};  

Thanks in advance :-).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T12:42:12+00:00Added an answer on May 21, 2026 at 12:42 pm

    The above code actually compiles fine for me in g++, assuming I rename the second one (inner i) to inner i2.

    This is the exact code I compiled in g++:

    class temp  
    {  
        public:
    
        class inner
        {
        public:
            inner(int a = 0) : memberInt(a) {}
            const int memberInt;
        };
    
        temp(int i = 0) : member(i)  
        {  
        }  
    
        inner *i;
        inner i2;
        int member;  
    }; 
    
    
    int main()
    {
        return 0;
    }
    
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